sepesial BA
only two questions
Nomor 5b
[tex] \left( \frac{ {a}^{ - 3} . {b}^{4} }{ {c}^{ - 3}.a} \right)^{ - 2} \\ \\ = \left( \frac{ {a}^{ - 3 - 1}. {b}^{4} }{ {c}^{ - 3} } \right)^{ - 2} \\ \\ = \left( \frac{ {a}^{ - 4}. {b}^{4} }{ {c}^{ - 3} } \right)^{ - 2} \\ \\ = \left( \frac{ {a}^{8}. { {b}}^{ - 8} }{ {c}^{6} } \right) \\ \\ = \left( {a}^{8}. \frac{1}{ {b}^{8}}. \frac{1}{ {c}^{6} } \right) \\ \\ = \left( \frac{ {a}^{8}}{ {b}^{8} {c}^{6} } \right)[/tex]
[tex] \\ [/tex]
Nomor 5c
[tex] \frac{( {a}^{0}. {b}^{ - 1}) }{( { - a)}^{ - 2}. {b}^{5}} \\ \\ = \frac{(1 \: . \: {b}^{ - 1})}{ \frac{1}{ {( - a)}^{2} } \: . \: {b}^{5} } \\ \\ = \frac{ {b}^{ - 1} }{ \frac{1}{ {a}^{2} } \: . \: {b}^{5} } \\ \\ = \frac{1}{ \frac{1}{ {a}^{2} }. {b}^{5 + 1} } \\ \\ = \frac{1}{ \frac{1}{ {a}^{2} }. {b}^{6} } \\ \\ = \frac{1}{ \frac{ {b}^{6} }{ {a}^{2} } } \\ \\ = \frac{ {a}^{2} }{ {b}^{6} } [/tex]
Jawab:
(5b.)
[tex]=\displaystyle\sf\frac{a^8}{b^8c^6}[/tex]
(5c.)
[tex]=\displaystyle\sf\frac{a^2}{b^6}[/tex]
Penjelasan:
(5b.)
a⁻²⁽⁻³⁻¹⁾ b⁴⁽⁻²⁾ c⁻²⁽⁻⁽⁻³⁾⁾
= a⁻²⁽⁻⁴⁾ b⁴⁽⁻²⁾ c⁻²⁽³⁾
= a⁸ b⁻⁸ c⁻⁶
[tex]=\displaystyle\sf\frac{a^8}{b^8c^6}[/tex]
(5c.)
a⁰(-a)²(b⁻¹⁻⁵) = a⁰⁺² b⁻⁽¹⁺⁵⁾
= a² b⁻⁶
[tex]=\displaystyle\sf\frac{a^2}{b^6}[/tex]
(xcvi)
[answer.2.content]
